5t^2-1.6t-2=0

Solution for 5t^2-1.6t-2=0 equation:

5t^2-1.6t-2=0

a = 5; b = -1.6; c = -2;
Δ = b2-4ac
Δ = -1.62-4·5·(-2)
Δ = 42.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{42.56}}{2*5}=\frac{1.6-\sqrt{42.56}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{42.56}}{2*5}=\frac{1.6+\sqrt{42.56}}{10}
$